Integrand size = 25, antiderivative size = 71 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{(a+a \sin (c+d x))^2} \, dx=\frac {\sec (c+d x)}{5 d (a+a \sin (c+d x))^2}-\frac {2 \sec (c+d x)}{15 d \left (a^2+a^2 \sin (c+d x)\right )}+\frac {4 \tan (c+d x)}{15 a^2 d} \]
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Time = 0.08 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {2938, 2751, 3852, 8} \[ \int \frac {\sec (c+d x) \tan (c+d x)}{(a+a \sin (c+d x))^2} \, dx=\frac {4 \tan (c+d x)}{15 a^2 d}-\frac {2 \sec (c+d x)}{15 d \left (a^2 \sin (c+d x)+a^2\right )}+\frac {\sec (c+d x)}{5 d (a \sin (c+d x)+a)^2} \]
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Rule 8
Rule 2751
Rule 2938
Rule 3852
Rubi steps \begin{align*} \text {integral}& = \frac {\sec (c+d x)}{5 d (a+a \sin (c+d x))^2}+\frac {2 \int \frac {\sec ^2(c+d x)}{a+a \sin (c+d x)} \, dx}{5 a} \\ & = \frac {\sec (c+d x)}{5 d (a+a \sin (c+d x))^2}-\frac {2 \sec (c+d x)}{15 d \left (a^2+a^2 \sin (c+d x)\right )}+\frac {4 \int \sec ^2(c+d x) \, dx}{15 a^2} \\ & = \frac {\sec (c+d x)}{5 d (a+a \sin (c+d x))^2}-\frac {2 \sec (c+d x)}{15 d \left (a^2+a^2 \sin (c+d x)\right )}-\frac {4 \text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{15 a^2 d} \\ & = \frac {\sec (c+d x)}{5 d (a+a \sin (c+d x))^2}-\frac {2 \sec (c+d x)}{15 d \left (a^2+a^2 \sin (c+d x)\right )}+\frac {4 \tan (c+d x)}{15 a^2 d} \\ \end{align*}
Time = 0.49 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.15 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{(a+a \sin (c+d x))^2} \, dx=-\frac {\sec (c+d x) (-80-5 \cos (c+d x)+64 \cos (2 (c+d x))+\cos (3 (c+d x))-80 \sin (c+d x)-4 \sin (2 (c+d x))+16 \sin (3 (c+d x)))}{240 a^2 d (1+\sin (c+d x))^2} \]
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Result contains complex when optimal does not.
Time = 0.28 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.04
method | result | size |
risch | \(-\frac {8 \left (5 i {\mathrm e}^{2 i \left (d x +c \right )}+5 \,{\mathrm e}^{3 i \left (d x +c \right )}-i-4 \,{\mathrm e}^{i \left (d x +c \right )}\right )}{15 \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )^{5} d \,a^{2}}\) | \(74\) |
parallelrisch | \(\frac {-2-30 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-40 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-40 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-8 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{15 d \,a^{2} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}\) | \(87\) |
derivativedivides | \(\frac {-\frac {1}{4 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}+\frac {4}{5 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}-\frac {2}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{4}}+\frac {7}{3 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}-\frac {3}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}+\frac {4}{16 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+16}}{d \,a^{2}}\) | \(100\) |
default | \(\frac {-\frac {1}{4 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}+\frac {4}{5 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}-\frac {2}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{4}}+\frac {7}{3 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}-\frac {3}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}+\frac {4}{16 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+16}}{d \,a^{2}}\) | \(100\) |
norman | \(\frac {-\frac {2 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}-\frac {8 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d a}-\frac {2}{15 a d}-\frac {8 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{15 d a}-\frac {8 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d a}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5} a}\) | \(114\) |
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Time = 0.29 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.13 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{(a+a \sin (c+d x))^2} \, dx=\frac {8 \, \cos \left (d x + c\right )^{2} + 2 \, {\left (2 \, \cos \left (d x + c\right )^{2} - 3\right )} \sin \left (d x + c\right ) - 9}{15 \, {\left (a^{2} d \cos \left (d x + c\right )^{3} - 2 \, a^{2} d \cos \left (d x + c\right ) \sin \left (d x + c\right ) - 2 \, a^{2} d \cos \left (d x + c\right )\right )}} \]
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\[ \int \frac {\sec (c+d x) \tan (c+d x)}{(a+a \sin (c+d x))^2} \, dx=\frac {\int \frac {\sin {\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}}{\sin ^{2}{\left (c + d x \right )} + 2 \sin {\left (c + d x \right )} + 1}\, dx}{a^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 204 vs. \(2 (65) = 130\).
Time = 0.23 (sec) , antiderivative size = 204, normalized size of antiderivative = 2.87 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{(a+a \sin (c+d x))^2} \, dx=\frac {2 \, {\left (\frac {4 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {20 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {20 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {15 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + 1\right )}}{15 \, {\left (a^{2} + \frac {4 \, a^{2} \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {5 \, a^{2} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} - \frac {5 \, a^{2} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac {4 \, a^{2} \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} - \frac {a^{2} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}}\right )} d} \]
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Time = 0.40 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.32 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{(a+a \sin (c+d x))^2} \, dx=-\frac {\frac {15}{a^{2} {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right )}} - \frac {15 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 30 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 40 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 50 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 7}{a^{2} {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}^{5}}}{60 \, d} \]
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Time = 11.71 (sec) , antiderivative size = 159, normalized size of antiderivative = 2.24 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{(a+a \sin (c+d x))^2} \, dx=\frac {\frac {2\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6}{15}+\frac {8\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{15}+\frac {8\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{3}+\frac {8\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{3}+2\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{a^2\,d\,\left (\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )-\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )\,{\left (\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )+\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}^5} \]
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